Hi,
During a PC PSU conversion to a bench lab, in most cases a dummy load is needed to the 5V rail.
Why in a lot of articles, and also here on the forum, a resistor 10Ω 10W is chosen as a dummy load or even some heat sink is applied to this resistor ?
Ohms law + formula for a power... we can take a regular/simplest 1KΩ resistor (for instance), so it will put through 5V / 1KΩ= 5mA and dissipate just 25mW
Why not do this instead of using a heatsink and/or purchasing some 10watts components/sandbar.
Am I right ?
What do I miss ?
BR
During a PC PSU conversion to a bench lab, in most cases a dummy load is needed to the 5V rail.
Why in a lot of articles, and also here on the forum, a resistor 10Ω 10W is chosen as a dummy load or even some heat sink is applied to this resistor ?
Ohms law + formula for a power... we can take a regular/simplest 1KΩ resistor (for instance), so it will put through 5V / 1KΩ= 5mA and dissipate just 25mW
Why not do this instead of using a heatsink and/or purchasing some 10watts components/sandbar.
Am I right ?
What do I miss ?
BR