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Hi folks,
Since I wanted to revise the basic configuration of BJT, I read this chapter from Purdue University based on the Book of Sedra (https://engineering.purdue.edu/wcch...s/ece255Lecture_13_Feb27_BJT_Basic_Config.pdf) at page 13 where he wrote Ro=re which I do not agree as if it was me it should be Ro=re+Rsig/(B+1).
Then I come into another resource from Kansas University at page 11 : (https://www.ittc.ku.edu/~jstiles/41...ps/The Common Collector Amplifier lecture.pdf). where it state the definition of calculating the output resistance as : Ro=Vo_oc/Io_sc ,where Vo_oc is the open-circuit output voltage and sc is the short-circuit output
Actually, if I use the Kansas' method, I find the same result as when I just short circuit all voltage source and open circuit all current source and apply Vtest and see Itest.
Second question is : how do we do with the gm*Vbe current source in such situation, is it considered high impedance, therefore open circuit?
Since I wanted to revise the basic configuration of BJT, I read this chapter from Purdue University based on the Book of Sedra (https://engineering.purdue.edu/wcch...s/ece255Lecture_13_Feb27_BJT_Basic_Config.pdf) at page 13 where he wrote Ro=re which I do not agree as if it was me it should be Ro=re+Rsig/(B+1).
Then I come into another resource from Kansas University at page 11 : (https://www.ittc.ku.edu/~jstiles/41...ps/The Common Collector Amplifier lecture.pdf). where it state the definition of calculating the output resistance as : Ro=Vo_oc/Io_sc ,where Vo_oc is the open-circuit output voltage and sc is the short-circuit output
Actually, if I use the Kansas' method, I find the same result as when I just short circuit all voltage source and open circuit all current source and apply Vtest and see Itest.
Second question is : how do we do with the gm*Vbe current source in such situation, is it considered high impedance, therefore open circuit?
