Just checking an algorithm I stumbled on a slightly interesting result. The expression is
5/(1.5**4).
Needs answer to 9 decimal points.

 

What makes it interesting? There's no way to get the wrong answer because they included parenthesis to force an order of operations that's already understood.

 

My old favorite from back in the heyday of the hand calculator is 987654321 ÷ 123456789.

 

Just checking an algorithm I stumbled on a slightly interesting result. The expression is
5/(1.5**4).
Needs answer to 9 decimal points.

What is the double **?
\(\frac{5}{1.5•4}\)?

 

Sorry. I'll rephrase that in Basic: 5/1.5^4 (without redundant parentheses).
Just means raise to the power. It's the Fortran version.

 

Thanks.
That changes the interesting level a little.

Spoiler

0.987654321

 

\(x=\frac{5}{1.5^4}\)

Practicing my LaTex skills.



The M$ calculator can handle more than 8 digits.

Spoiler

I get 0.98765432098765432098765432098765

 

My old favorite from back in the heyday of the hand calculator is 987654321 ÷ 123456789.

And you only need one decimal place for the answer.

 

\(\frac{987654321}{123456789}=8.000000072900000663390006036849\)

Trolling Moderator style.

 

\(\frac{987654321}{123456789}=8.000000072900000663390006036849\)

OK, you only need 1 decimal place for a engineering answer.

 

\(\frac{987654321}{123456789}=8.000000072900000663390006036849\)

Trolling Moderator style.

Just curious. What did you use to get that many digits? Excel drops anything past 729. Another calculator I have gives ...72900001 using double precision and ...72900000664 using float80.

 

\(x=\frac{5}{1.5^4}\)

Practicing my LaTex skills.

View attachment 227764

The M$ calculator can handle more than 8 digits.

Spoiler

I get 0.98765432098765432098765432098765

Yes, that's why I said to 9 decimal digits of precision. The repeat count gets approximated.
Could not have been exact with a factor of 3 in the denominator, really!
My old calculator displays 9 digits but has an accuracy to about 12. You have to subtract some MSD's to see the remainder. Which is how I came across this.

 

Just curious. What did you use to get that many digits? Excel drops anything past 729. Another calculator I have gives ...72900001 using double precision and ...72900000664 using float80.

The M$ calculator can handle more than 8 digits.

 

M$

Ah, so Windows calculator. I gather it uses bignum (precision limited by system memory), so that would do it.

 

Now and then M$ does something right.