What about eliminating R1 and R2, and adding two clip diodes inverse parallel with R4? Maybe keeping R1 as a current limiter.How about this?
ak
What about eliminating R1 and R2, and adding two clip diodes inverse parallel with R4? Maybe keeping R1 as a current limiter.How about this?
That's great! Thanks!How about this?
I don't think the initial transient will be something you can hear.
View attachment 130832
Even better, I get that the diodes are clipping the wave at 0.7 V, but I'm not getting how that 'tooth saw' wave, in V1, is being produced.
It's caused by the limited low frequency response of the capacitor as it provides current through the diode clippers.I'm not getting how that 'tooth saw' wave, in V1, is being produced.
It's simply a function of the RC time-constant where R is the equivalent resistance of all the resistors.Kind of weird how a resistance to the ground decreases that time.
Sorry about reopening the post, but I was testing in multisim and the only thing the diodes are doing is limiting the voltage, instead of getting a sinve wave of 377mV I get 100mV or less.What about eliminating R1 and R2, and adding two clip diodes inverse parallel with R4? Maybe keeping R1 as a current limiter.
ak
Yeah I just checked the output, it will also take more time to stabilize, converting that to a sine wave (pic below).1 K and 1 uF is a time constant of 1 ms, so there should be considerable sag in a 5 ms period - as shown in your images. Wally's circuit time constant is four times larger, with much less sag.
ak
Working with R4 as a voltage divider.And what is R1 doing in this montage?