Hello, When i will build it in my lab and i will turn on the power supply.
I have a pulse goint from R10 into C4.
capacitor has the tendency to be continues with voltage , so id there is a voltage jump on one side it will transform to the other side .
So the quetion is about the capacitor.
When we send a pulse on P12 How C4 will behave?
What is the exact physical behavior of this capactior C4 in this situation?
Thanks.

 

https://www.electronics-tutorials.ws/rc/rc_1.html

The waveform will be distorted by the changing base current through Q1

 

Hello , this is a very fundamental intuition I miss .
Suppose I have a pulse of 0 to 12 V coming from one side , the other side of the capacitor cannot jump 0 to 12 V also.
What does it do in the siculstances?
Thanks .

 

Suppose I have a pulse of 0 to 12 V coming from one side...
(some text removed for clarity)

It charge slowly (as determined by the resistance, base current, and capacitances involved) toward the peak voltage of the pulse. When the pulse goes back to zero volts, the voltage across the capacitor will begin discharging toward zero volts.

 

Hello ,My focus is on the C4 capacitor.I was told that the difference between situation 1 when C4 is grounded the base of Q1 starts from 0V.

When C4 in parralel to R10 then C4 starts from 15V. What is the inner capacitance mechanism that caused the difference?
Thanks.

 

UPDATE:
Hello , What about the situation when i move C4 to be parralel to R10.
There is a basic law regarding capacitors shown below.
"The principle of continuity of capacitive voltage says: In the absence of infinite current, the voltage across a capacitor cannot change instantaneously."

looking at the following situation how does the capacitor acts?
one leg feel rise of zero to 12V what does the other leg get because of that and why?

 

looking at the following situation how does the capacitor acts?

Initially the capacitor has no charge and acts as a short circuit across R10. If only P12 is activated nothing happens and the capacitor remains discharged across R10. If M12 is pulsed while P12 is pulsed the capacitor will begin to charge through Q2 ,R11 and the base-emitter junction of Q1. This will provide a brief delay before the collector of Q1 goes High and only if the duration of both pulses is of sufficient duration to complete a cycle.

 

These are unusual questions for an electrical engineer to be asking.

 

Hello, When i will build it in my lab and i will turn on the power supply.
I have a pulse goint from R10 into C4.
capacitor has the tendency to be continues with voltage , so id there is a voltage jump on one side it will transform to the other side .
So the quetion is about the capacitor.
When we send a pulse on P12 How C4 will behave?
What is the exact physical behavior of this capactior C4 in this situation?
Thanks.

View attachment 331844

In this configuration assuming that C4 is discharged the output of Q1 will go High as soon as a pulsed is applied at P2 because
at this point C4 is a short circuit. As C4 begins to charge the output voltage on Q1 will eventually decrease to zero and all depending on the duration of P2.
C4 must be discharge before this can happen again by pulsing M12 while P12 is Off for a duration long enough to discharge C4 thoroughly through R11 and Q2.
I don't see the need for a negative supply and Q1 should have a base resistor or Q1 will most likely be damaged. Add R12!

 

Do you have specific objectives, or are you showing example circuits to learn what they can do.

Edit: Since you already have LTspice running, you can change the parameters you mention and see the results very quickly.

 

As stated in post#10: What is the intended function of the circuit?? What is the application?? What is the desired output voltage or current profile??
And one more question: What sort of electrical engineer IS the TS??

 

As stated in post#10: What is the intended function of the circuit?? What is the application?? What is the desired output voltage or current profile??
And one more question: What sort of electrical engineer IS the TS??

This thread is likely related.

 

It seems that thread was abandoned. I understand why!
No assistance until the questions are answered.