buck converter and supercapacitor

ScottWang

Joined Aug 23, 2012
7,501
I measure the current and is less than 200mA, I guess the 2N2222 can handle up to 800mA according to the spec
That is choose as 2SC1384(1A) is better, for the power dissipation, you should choose a rating Ic is three times or more of calculation (or measuring) values.
 

crutschow

Joined Mar 14, 2008
38,530
I measure the current and is less than 200mA, I guess the 2N2222 can handle up to 800mA according to the spec
Yes, that should be okay.
I thought you didn't know how much current the motor took since you had no specs on the motor and didn't use that load for your simulated motor.
 

ScottWang

Joined Aug 23, 2012
7,501
I measure the current and is less than 200mA, I guess the 2N2222 can handle up to 800mA according to the spec
That is using as 2SC1384(1A) is better, choosing a rating Ic values for three times or more of calculation or measuring values is good for power dissipation.
I have two 2.7v 10F supercaps in series
When you in series with two supercapacitors then you should in parallel with a balancing resistor (Please see the section -- Why do ultracapacitors require balancing? What are the balancing methods?) for each supercapacitor, the R values is :
R = (Vcc/2)/I
= 2.5V/114 μA
= 21.923K
You can choose two 20K.
 

crutschow

Joined Mar 14, 2008
38,530
Any idea why the diode is letting the voltage pass to the regulator side?
It's not, unless the circuit is wired differently than the schematic.

I think the capacitor discharge is through the transistor resistors and the lack of a resistor on the MAX809 output as I previously stated.
 

Thread Starter

hsaul17

Joined Jul 12, 2018
17
That is using as 2SC1384(1A) is better, choosing a rating Ic values for three times or more of calculation or measuring values is good for power dissipation.

When you in series with two supercapacitors then you should in parallel with a balancing resistor (Please see the section -- Why do ultracapacitors require balancing? What are the balancing methods?) for each supercapacitor, the R values is :
R = (Vcc/2)/I
= 2.5V/114 μA
= 21.923K
You can choose two 20K.
I didn't know that, thanks for the tip
 

Thread Starter

hsaul17

Joined Jul 12, 2018
17
It's not, unless the circuit is wired differently than the schematic.

I think the capacitor discharge is through the transistor resistors and the lack of a resistor on the MAX809 output as I previously stated.
I will re-wire again the circuit, maybe I did something wrong, thanks for all your help guys, I learned a lot
 
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