a) I got from Kirchoff that Vbb=0.7V
b) I assumed Bdc*Ib=Ic and that Ic=Ie. I then calculated Ic by using kirchoff for CE and got Ib=5.58*10^-3A
From there I got Ib=5.85*10^-5A so Vbb=8.89V
c) Here I'm really not certain, I put Vc=0V and therefore assumed Vcc must drop across the 1000ohm's (R1) so
12=1000*Ic ----> Ic = 1.2*10^-3
I don't know if I can assume Ie=1.2*10^-3A but if I do the voltage drop across R2 would be 1.2V.
So I would have 4V-40.000ohm*Ib-0.7V-1.2V=0
and therefor Ib=5.25*10^-5A.
So I would guess the transistor would be on but it wouldn't be on the linear phase, that is Ib*Bdc ≠ Ic
Really uncertain about this so any help or tips well appreciated!