I know big enough resistor will limit the current, that is besides the point. In the last example of common base we saw batteries in series and no damage to the smaller one as Danko nicely pointed out. Consequently, i asked why in the case of transistor failure in common emmiter configuration, smaller battery does (potenetially) get damaged. In both examples current flows from big to small battery, but only in the latter damage potentially happens. What is the cause of this, is it the polarity or? To address your question, i study those too, i just want to clear up these details.hi N,
If there is a high value load resistor between the two batteries, that will limit the current flowing from the big battery to the small battery, the small battery will not be immediately be damaged, it could fail later due to over charging.
Why don't you study a more practical/everyday configuration of the BJT, it will help you better understand the transistors operation.?
E
Very good, overflow kills. TnxTo damage, the battery you need "short" directly two batteries together so that the short-circuit current will start to flow.
I know base current is in most cases delivered from Vcc through a resistor and modulated by input signal.But your example with two batteries is highly theoretical. We never use this kind of a setup in real life.