Audio Amp Build Questions

Jony130

Joined Feb 17, 2009
5,598
Without Ce capacitor the gain is equal to
Av ≈ (Rc||RL)/(Re) But if you add Ce capacitor into the circuit the voltage gain will increase to
Av = gm*(Rc||RL)
where
gm - transconductance = Ic/26mV ≈ 40*Ic

Have you check you DC operation point without input signal? Can you show as result?
 
Last edited:

LvW

Joined Jun 13, 2013
2,026
To complete the story about the bypass capacitor Ce:

Ce is not only influencing the amount of gain - it also has influence on the QUALITY of gain. This means the following:
Without Ce we have signal feedback due to Re, which offers some advantages:
* gain value less suszeptible to BJT tolerances and temperature changes,
* better signal quality (less distortions) due to linearizing effect of feedback
* larger signal input resistance.
 

Thread Starter

Joster

Joined Jun 12, 2013
95
Thanks! I will use that formula for my circuit and calculate it out. Someone told me that the voltage gain is determined by Rc/Re. Is this true?
 

Jony130

Joined Feb 17, 2009
5,598
Last edited:

Shagas

Joined May 13, 2013
804
Yest it's true but only when:
- Collector resistance (Rc) is much larger then the load resistance (RL).
Don't you mean it the other way around ?
When RL is very large in respect to RC then we can consider that the gain is close to Rc/Re .
In fact it's trully Rc/Re when we haven't connected a load.

Correct me if i'm wrong.
 

LvW

Joined Jun 13, 2013
2,026
Thanks! I will use that formula for my circuit and calculate it out. Someone told me that the voltage gain is determined by Rc/Re. Is this true?
This simplified expression shows you that for sufficient negative signal feedback the gain is primarily determined NOT by the active device but by the feedback elements.
This case is comparable to the gain expression -R2/R1 for an operational amplifier used as an inverting amplifier.
 
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