In other words, the problem is NOT asking you to create a 3-to-8 decoder at all!But my exercise says "Design a circuit that will produce a digit of even parity for a number of 3 binary digit (xyz) using:
a) decoder 2-4 (without using enable input and inverse outputs) and gates OR
But this is NOT the same problem that you described in your original post:Design a circuit that will produce a digit of even parity for a number of 3 binary digit (xyz) using:
a) decoder 2-4 (without using enable input and inverse outputs) and gates OR
These are two essentially unrelated problems. The only thing they happen to share is that each involves 2-4 decoders.How i can make one 3-8 decoder with (2) 2-4 decoders with out use enable input and without inverse outputs.
Actually, you don't. You can use a 2->4 decoder (without enable) to produce an AND gate and to produce a NOT gate. That means that it is a universal gate and that you can implement ANY Boolean function using just a bunch of 2-> decoders. Now, it may not be pretty, but it can be done.Hello,
You will NEED the select or enable inputs for making a 3->8 using 2 X 2->4 decoders.
Bertus
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