It is your project, you need to pick the durations. t=1.1RC for each monostable.

Think small caps and big resistors, 10KΩ - 1MΩ

R1,R3,R7 = 10KΩ
C1,C3,C4,C6,C7,C9 = 0.1µF
R9,10 = 1KΩ

 

I connected the circuit on a breadboard now and I'll connect it with the L293 driver... yes I chose them equal, the R's 330k except R1 is 470k and the C's 10u... I may change them as you said... C1 and the switch are not useful here.. it works good.. Actually I didn't understand the circuit good, after I finish the project, in summer I will read more about timers and I'll understand it later...
Thanks Bill

 

There is another thing, to feed the L293 logic from 6V I will use a 5.1V zener diode, I'll connect the zener in reverse in series with a resistor between 6V and the ground, what is the best value to choose for the resistor? 1k to 10k is good maybe?

 

It is the 555 Monostable 3 layers deep. If you were to make one X6 and connect LEDs to all of them it would scan down, a neat effect.

 

There is another thing, to feed the L293 logic from 6V I will use a 5.1V zener diode, I'll connect the zener in reverse in series with a resistor between 6V and the ground, what is the best value to choose for the resistor? 1k to 10k is good maybe?

Not sure what you're referring to. If you are talking signal conditioning then go with the lower resistor. You probably don't need it.

The other resistors you mentioned are fine.

Why not post a schematic from your side?

 

This is what I mean.. Is the value of the resistor accurate?

 

No it didn't work... the voltage at Vss is 2.2V at 1k and 2.3 at 500.. I want to use zener and not a voltage regulator IC since the current through Vss is very small.

 

ouff... the resistor should be around 20ohm.. I triggered the circuit by infrared LED.. everything is working good