It depends on the current you want for the LED.
Provide a return path for the LED current depending on which way the switch is positioned.What purpose do the transistors serve?
All that's needed for that is a ground. The transistors serve no useful purpose.Provide a return path for the LED current depending on which way the switch is positioned.
And how would that work when you throw the switch?All that's needed for that is a ground. The transistors serve no useful purpose.
Oh, yeah... I was looking at only one path. It would be cheaper to use two separate LEDs, but that isn't the question and maybe isn't even possible for the application.And how would that work when you throw the switch?
The two LEDs are in one package with only two leads.
Hmm, Seems like it should have kind of worked. But lets see.Here i a link to the LED info: http://www.mouser.com/ProductDetail/Lumex/SSF-LXH4RAHGW/?qs=/ha2pyFadugmkBHTmtEgaqztgm5EMmJxYKjYquuumdhJ4tcCmUk43g==
It is a red/green indicator. I don't know what the transistors do, but if the voltage is 6.3 VDC instead of 4.5VDC everything works.
The LED voltage should be 2.2 volts if the voltage on top is 4.5 volts like in your diagram.I tested the LED with 2 AA batteries, and it is okay. If I have 1.1VDC at the LED now, shouldn't I need a smaller resistor in place of the 82 ohm one? If I put a 120 ohm resistor, the voltage will be even lower, won't it?
Before you do that, mark up the drawing with the values you have then measure the voltage at each point and write it on the drawing.Maybe I'll try putting around a 40 ohm resistor in place of the 82 ohm rsistor to see what happens?
Yeah, Your ground kind of disappeared.View attachment 113764
Here is a more complete schematic. The relay shows only one side, and there are two circuits that it switches. I was a little confused about where I was finding the voltage. I went and spent some more time studying, and these are correct voltages. The two 100 ohm resistors used to go straight to ground, but I've had to do some ground referencing. Now the LED won't work. Sorry about the earlier posts.
by Duane Benson
by Jake Hertz
by Jake Hertz
by Jake Hertz