hint: review the output stage.View attachment 307735
Hi, i have been trying to o a all transistor binary counter using d latches but my pcb doesn't work. When i test it on simulation program everything is all right. Can you help me see where i have made a mistake?
I dont get it. Should I delete the J1 output?hint: review the output stage.
What will that change?I dont get it. Should I delete the J1 output?
review the NOR truth table.The only difference i can see is the lack of buffers but i don't think they change anything, but maybe this it the issue:
View attachment 307758 Is this resistor screwing me?
Thanks! i will try to break it down and understand what you said haha. For the simulation above i used https://logic.ly/demo/What simulator are you using?
The input to your transistor NOR gates is directly to the base of the transistor and the emitter is grounded. So the maximum
base voltage will be the Vbe of the transistor (and the current isn't limited). This will limit the output voltage of the stage driving
it to a "high" voltage of around 0.7 volts, much lower than Vcc.

https://en.wikipedia.org/wiki/Resistor–transistor_logics
Notice the resistors on the imputs before the transistor bases.
nice, i will try that on breadboardSo you are NOT simulating at the transistor level. The problem is that your basic transistor NOR gate is wrong so simulating
the logic using NOR gates doesn't show the problem but building with real transistors does.
Your NOR gate (built with transistors) should accept gnd or Vcc on each input and not load the inputs too much.
The output should switch between close to ground and Vcc.
PS: I'd prefer schematics with inputs toward the left, outputs toward the right, Vcc at the top and gnd at the bottom.
Your 1k collector resistors should go straight up and the NOR output should be to the right (not vertical).
View attachment 307816
I use LTSPICE it simulates at the transistor level (and runs locally and is free).
In your #1 post diagram the transistors Q17 Q18 Q19 Q20 don't have resistors on their inputs so they
load down the outputs driving them. Also the LED4 doesn't have a resistor so it's going to load down
the output driving it. Perhaps the LED should have it's own driving transistor.
Also in #1 where are the D latch inputs?

