Hello:

I have a simple common-emiiter voltage amplifier with a gain of 10. The emmiter resistor is partially bypassed.

Vcc = 20 V, Vc = 10.3 V, Ve = 4.8 V, Vb = 5.5 V, Vceg = 5.4 V and Icg = 3 mA. I thought that the upper and lower

clipping levels would be 5.4 V.

When I feed a 285 rms mV sine wave into the input, I obtain a 2.85 vrms output, it is at this point that clipping begins. Any help would be appreciated.

Thanks,

John

 

Welcome to AAC!

Please post a schematic.

 

Without a schematic it is difficult to tell. You say the emitter resistor is partially bypassed. I take that to mean there is an un-bypassed resistor in the emitter. This means that as the base voltage rises, the collector voltage will fall and the emitter voltage will rise so the collector voltage cannot drop that 5.4V that you mention as the emitter voltage is coming up to meet it.

 

Schematic, parts values, schematic, signal characteristics, schematic ...

You have a circuit with a transistor (secret part number) and, what, 5 or 6 other components. You have kept secret what the parts are, how they are connected, what the signal source is, and what the load is. Exactly what kind of answer do you think you are going to get?

ak

 

OK, that went well...

 

The emmiter resistor is partially bypassed.

What is the point of bypassing? What is the point of not including the details if it is worth bypassing?

gain of 10

At what frequency was the gain calculated?

When I feed a 285 rms mV sine wave into the input

At what frequency was the input?

I thought that the upper and lower clipping levels would be 5.4 V.

Based on hope... or calculations... or an internet reference... or a not from your mother...

 

A comment like this requires at least one exclamation mark! E

 

OP permanently banned for repeated profanities.
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