why do I get a different transfer function of Butterworth filter

Thread Starter

xinyancode

Joined Sep 22, 2015
2
Hi, everybody,

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I have deduced several times for the transfer function of 3rd order Butterworth low pass filter, but the transfer function I got is
vo(s)/vi(s) = 1/( 2S^3 + 4S^2 + 4S + 2 )

while the transfer function of this filter in textbook and many document is
vo(s)/vi(s) = 1/( S^3 + 2S^2 + 2S + 1 )

I don't know what the problem is in my deduction, can anyone help me?
 

MikeML

Joined Oct 2, 2009
5,444
117.gif
V(out) = V(yours); V(b00k) is wrong.

You can see that yours is more realistic. Think about what happens at low frequency; R1,R2 create a voltage divider of 1/2.
 
Last edited:

Thread Starter

xinyancode

Joined Sep 22, 2015
2
Hi, MikeML,

thank you so much for your help, I come to understand more about this problem. and your simulation is great, I will also learn to use LTSpice, it seems very powerful.

yet, I am still a little confused on why there is the gap between the two transfer function. Is it possible that other people consider the transfer function based on voltage source with the 1 ohm internal resister, while I only consider the ideal voltage source.

thank you again......
 

MikeML

Joined Oct 2, 2009
5,444
...
yet, I am still a little confused on why there is the gap between the two transfer function. Is it possible that other people consider the transfer function based on voltage source with the 1 ohm internal resister, while I only consider the ideal voltage source...
Not likely:

117a.gif
 
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