What is the IL(t) of the RL Circuit of the IL(t=0) = I ini

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arditshala

Joined Feb 14, 2018
1


See the Circuit in the Attached Files first ///

I have to find the current in the mash I L(t) so the mesh current but the initial I L(0) = I initial = 3 mAH, now I have the the I(t) when I assumed that t=0 which is:

I(t) = Vs/R (1 - e^((-R/L)*t)))

Then I have done everything again with the assumption that I L(0) = I ini and then I have got this equation:

I L(t) = Vs/R + (I ini - Vs/R) * e ^ ((-R/L) * T)

And then I have the given values: Vs=10V, R=1kOHM, L=1mH and I ini = 3mA

Then I substitute everything but the function is so weird (I also should get the I L(0) = 3mAH, but I dont) and I cannot even procede to do the Euler's explicit interation to plot the results, can anyone tell me if my equation is wrong, if it is can someone explain why and how can I fix it in order to work?
 

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WBahn

Joined Mar 31, 2012
30,076
Where is this I_ini = 3 mA coming from? Seems like it's being pulled out of thin air?

We can't tell you were you went wrong unless you show us the work that got you to where you are.
 
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