Wolframore
- Joined Jan 21, 2019
- 2,609
I'm 100% in agreement with you on this one. I'm sorry to the TP, but they have so little actual comprehension of the subject that they have no business trying to teach anyone anything about it.Then I sincerely suggest that you teach some other subject and not electricity and electronics.
From where I sit it's only "unresolved" to one person. Guess who?together, in settling these unresolved issues.
I would start another thread for questions on the subject that's absent from the IMO trolling of the OP.Can you guys tell me if you agree with this, and such explanation suits to the further question, what happens to two wires connected to an AC source? That is, the capacitive charge moving back and forth, and leaving excess electrons on one terminal or the other?
That's great. Thanks. Now please put a resistor in that circuit and show the close-up view of the wire on each side of the resistor.
Let me ask you a question,That's great. Thanks. Now please put a resistor in that circuit and show the close-up view of the wire on each side of the resistor.
No difference. And no potential difference, either. On the other hand, in this experiment, the wires and the resistor have significantly different resistances, which divides the circuit into the bottom (B) leg which has a measurable negative electrical potential relative to the top (A) leg for the duration of the discharge. The current may be the same in both legs at any moment during the hour it takes to discharge the capacitor, but it seems to me that something must be different in the A and B legs to account for the potential difference.Let me ask you a question... If you have a wire and a resistor of same resistance. What are their electrical differences? ...Just think ohms law.
If there is "nothing physically different between P and Q," then why does the current flow from P toward Q instead of the reverse?There is no difference.
Conduct this thought experiment.
Connect a very long wire between point A and point B. Current X flows through the wire from point A to point B.
Now take an infinitesimally small portion of the wire and consider what happens between the two ends of this small portion of wire. We will name the two ends of this portion P and Q.
The potential difference between P and Q is infinitesimally small, almost zero.
And still, current X flows between P and Q.
Current flow is the aggregate movement of charges in the medium. There is nothing physically different between point P and Q, or point A and B.
Well, I don't have a degree in Electrical Engineering, but I do have a degree in Mathematics (with honors)...You are still attempting to get a simple answer to a complex situation. Get yourself an Electrical Engineering degree, study Maxwell's equations and the Lorentz force law among other things. Then you may be able to understand what you are clearly missing now. You will never be get anywhere as long as you are fixated on electrons piling up somewhere.
Here's what you're missing- there is no 'pile up' of electrons in this specific case. Electrons cannot pile up because voltage is unchanging. There is a specific potential being lost across the resistor, and so electrons don't 'pile up'. Initially, there is no resistance- it takes some incredibly small amount of time for the resistor to resist-- and as it does, the flow slows down throughout the entire circuit simultaneously....is the electron "pile up" in or on or around the surface of the wire in the B-leg of the circuit near the bottom of the resistor, and a corresponding dearth of electrons in or on or around the surface of the wire in the A-leg of the circuit near the top of the resistor.
Why should I prefer your model to the contrary [correction: more comprehensive] model presented by Chabay & Sherwood?Here's what you're missing- there is no 'pile up' of electrons in this specific case. Electrons cannot pile up because voltage is unchanging. There is a specific potential being lost across the resistor, and so electrons don't 'pile up'. Initially, there is no resistance- it takes some incredibly small amount of time for the resistor to resist-- and as it does, the flow slows down throughout the entire circuit simultaneously. That's how the physics actually works.
My model is not contrary to their model. The fact that you think it is, shows your lack of comprehension. Not being mean, just stating the obvious. Your problem is you can't wrap your mind around the resistor because the problem is simply too complex for you Instead, you should replace the resistor with a battery and then try to understand how the capacitor actually behaves at the electron level in both DC and AC environments.Why should I prefer your model to the contrary [correction: more comprehensive] model presented by Chabay & Sherwood?