Hi E!
The L/C is a nominal 1K load resistance, so 5 in parallel would be a 200R load, at say 5V, that is 25mA
I cant follow your calculation:
I I use 6 load scales. (Its easier then to calculate the xy postition)
So its 1 K for each L/C?
1K * 4 * 6 = 24 K
u/r=i;
5V/24K= 208,33 mA ?
The HX bypass transistor will be OK for this current level.
Is this transistor in the hx711 module? what does it?
The HX711 will also accept a 5V power source, taking approx 1.5mA for its internal circuitry.
Are there any other modules in the project.??
No other modules in the project
yes, 5v from a USBI am assuming that your Arduino is being powered by either a 5v from a USB or the onboard 5V reg with say a 9V DC source.?? [battery?]
E
The L/C is a nominal 1K load resistance, so 5 in parallel would be a 200R load, at say 5V, that is 25mA
I cant follow your calculation:
I I use 6 load scales. (Its easier then to calculate the xy postition)
So its 1 K for each L/C?
1K * 4 * 6 = 24 K
u/r=i;
5V/24K= 208,33 mA ?
The HX bypass transistor will be OK for this current level.
Is this transistor in the hx711 module? what does it?
The HX711 will also accept a 5V power source, taking approx 1.5mA for its internal circuitry.
Are there any other modules in the project.??
No other modules in the project