Ok, may have to be tomorrow.OK, something in the circuit is not as in the schematic.
Disconnect the sensor and the motor (no point in it running for this).
Measure the voltage at the wiper of the pot or the base of TR1, whichever is easier, and adjust the pot for the lowest voltage (should be close to zero).
Now measure these voltages:
TR1 collector and emitter.
TR2 base, collector and emitter.
There is a relay driving the pump, so it is the relay drop-out voltage which is the determining factor.Even if you add a load simulating the pump, the simulation shows there is nearly 3V on the pump when it is supposedly 'off'. That may be enough to keep the pump running.
The current with the pump full on is 2.7A so it might be possible to run the system without the relay? Most FETs would be fine with that load.There is a relay driving the pump, so it is the relay drop-out voltage which is the determining factor.
It has hysteresis on the back end and since the TS has already made the pcb it would be an easy mod. Does it really need hysteresis on the front end? I guess that would depend on how long it takes for the fluid level to drop below the terminal.Yours is a completely different circuit. The original circuit is a Schmitt trigger comparator. Your circuit has no hysteresis, and will not work well in this application.
And how much the liquid sloshes around especially while being pumped perhaps.I guess that would depend on how long it takes for the fluid level to drop below the terminal.
Ah, missed that.There is a relay driving the pump
That is the problem with the circuit. I have the exact relay used and the dropout voltage is 1.5volts.Even if you add a load simulating the pump, the simulation shows there is nearly 3V on the pump when it is supposedly 'off'. That may be enough to keep the pump running.
If that is the problem it will become clear when TS has measureed the voltages.That is the problem with the circuit. I have the exact relay used and the dropout voltage is 1.5volts.
This circuit is an example of how to do something that is relatively simple, with fewer parts, into something difficult with unnecessary complexity. Here is a much simpler version:Hi all,
I have built a water level feed control for an electrolyser using the attached circuit but it doesn't quite work as I would like it to.
The sensor consists of two Allen screws in the side of the electrolyser body (test rig) acting as the sensor and when the water level falls below the top screw the motor starts up as expected. However, when the water level rises back to the top screw the motor doesn't switch off.
There is a 10k pot in the circuit that doesn't seem to make any difference to how the device works and what I'm asking is how can I make the motor stop immediately once the water (0.05M KOH) rises to the top screw.
I'm thinking that perhaps the 330uF cap is holding the base of the first transistor on for too long? So maybe a smaller value like 50uF or a 1k bleed resistor across it?
Thoughts appreciated.
Jules
It's not the sensitivity causing the problem. It's the 3 volt offset and the relay (see post #51). Changing R2 and removing the pot will not change the offset.The circuit does not work because it has terrible sensitivity.
The circuit works it's just the relay used is to sensitiveIt's another silly circuit that works only due to side effects.
by Aaron Carman
by Jake Hertz
by Jake Hertz