Water detection circuit

Thread Starter

Xertu

Joined Jul 29, 2025
4
Hi,

I'm analyzing this water detection circuit and have a couple of questions.

As I understand it, the circuit is intended to drive the speaker when the two prongs detect water. A small current through the water should switch on the Darlington transistor (T1). Once T1 is on, there should be no current flowing to IC1's reset pin, allowing the oscillator to run and the output to turn on.

However, in my simulation, it seems to work in the opposite way. The output is on until water is detected.

  1. Is there an error in my simulation, or is a NOT gate needed between R2 and IC1's reset pin?
  2. I'm also confused about the purpose of R4. Is it simply there to limit the current into T1?
Thanks in advance.

IMG_2938.jpgNäyttökuva 2025-11-05 160108.pngNäyttökuva 2025-11-05 155927.png
 

schmitt trigger

Joined Jul 12, 2010
2,027
For the 555 to run, the reset must be held high. For that to happen the darlington MUST be non-conducting.
And that only happens when the probes are dry.
You have to invert the polarity with another transistor

EDIT: Wait, there is a resistor missing on the transistor base to Vcc
 
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Thread Starter

Xertu

Joined Jul 29, 2025
4
Eric;
The drawing style appears to be from Elektor magazine.

EDIT: upon closer inspection, R4 should go to the base instead of the collector. That is it
Why should R4 go to the base? Would that not inhibit T1 from switching as the current is likely to be very small.
 

ericgibbs

Joined Jan 29, 2010
21,390
Hi X,
T1 is a Darlington transistor, it has a high input impedance and a high gain.

T1 needs to be ON conducting to set the RESET low to stop the 555 astable circuit

So it needs a bias resistor from its Base to the VCC supply

E
 

ericgibbs

Joined Jan 29, 2010
21,390
hi X,
Checkout this LTSpice simulation.
E
Reversed the change in water level, makes it easier to follow.
EG 1817.png
 
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