I have been working on a project to get the voltage of around 6 thousand DC through Villard cascade voltage multiplier. The method I used to implement was:
1. step down the AC voltage of 220V 50Hz down to 12V same frequency with transformer
2. Step up the 12V 50 Hz to 220V 50Hz with step up transformer with output current of 70 mA
3. With Different Villard cascade voltage multiplier stages, theoretically gained around 6000 Volts DC
The problem I'm facing now is that the spark distance and the intensity iss too small to my purpose and around 1cm spark is producing with much low intensity.
+ Capacitor are rated with 400V
+ Diode are of maximum current around 10A one
Any help would be appreciated,
Thanks

 

Show us a schematic of your circuit; specifically, the capacitor values.

 

Show us a schematic of your circuit; specifically, the capacitor values.

They don't have any value on them. I just bought them due to require voltage of 400V

 

I just bought them due to require voltage of 400V

You're severely overstressing the capacitors. It's not safe for this thread to continue.

 

You're severely overstressing the capacitors. It's not safe for this thread to continue.

I just mentioned that output current of the Transformer is 70mA. They must not be over stressing

 

I just want to ask if i increase the transformer output current. will there be any improvement in the spark and anthing?

 

I just mentioned that output current of the Transformer is 70mA. They must not be over stressing

The capacitors are rated for 400V and you're subjecting them to up to 6kV. Don't you see that as a problem?

 

The capacitors are rated for 400V and you're subjecting them to up to 6kV. Don't you see that as a problem?

Did you know that the voltage across the capacitor is double the input voltage, not output voltage.?

 

Did you know that the voltage across the capacitor is double the input voltage, not output voltage.?

To get 6kV, you need multiple stages cascaded.

 

To get 6kV, you need multiple stages cascaded.

yeah. And for that the voltage across each capacitor is double the input. And when all capacitor are cascaded in series then voltage is sum up from the end of the stage with respect to the input side, not between capacitor

 

This thread was locked for the safety reason.