I have a 12 volt source that I need to boost to 19.5 DC to run a laptop and back down again to charge a battery to run a 12V inverter to run a monitor and other things. How would you guys suggest that I proceed?
Buy what you need.I have a 12 volt source that I need to boost to 19.5 DC to run a laptop and back down again to charge a battery to run a 12V inverter to run a monitor and other things. How would you guys suggest that I proceed?
Use a dc-dc boost regulator to get the 19.5Vdc from the 12V source.I have a 12 volt source that I need to boost to 19.5 DC to run a laptop and back down again to charge a battery to run a 12V inverter to run a monitor and other things. How would you guys suggest that I proceed?
The battery type is Lithium ion.Use a dc-dc boost regulator to get the 19.5Vdc from the 12V source.
Run the 12V source directly to charge the battery (what type), and run the monitor and other things.
It would be inefficient to increase the voltage and then reduce it again.
I'm confused.I don't want to battery back up that voltage source.
Still does not make sense.I would much rather take the power from the 12 volt source to run my own system, which has its own battery.
Thread starter | Similar threads | Forum | Replies | Date |
---|---|---|---|---|
C | Resonant PLL Circuit | General Electronics Chat | 12 | |
R | Dual voltage dc system - 12V and 24V. | General Electronics Chat | 20 | |
![]() |
Voltage limit from bicycle generator | Power Electronics | 8 | |
A | Effective voltage reduction from 3.3v to 400mv without introducing temporal delay | Power Electronics | 3 | |
E | Thevenin's Theorem | Homework Help | 5 |
by Robert Keim
by Aaron Carman
by Aaron Carman
by Aaron Carman