Hello ... This is my first post and i hope from the members here to help me ...

In the circuit above I want to calculate the gain of the amplifier ... there is two ways to do it ... one is the regular and second it to calculate the equivalent resistance for R2, R3, R4 ... Can you help me in getting the equivalent resistance?

Thanks in advance

 

I really don't know why buy to find equivalent resistance you need:
Fin Rin of a open-circuit ( R4 open)
Rop = R2 + R3
Then you need to find Rin of a short circuit (R4 connect to the GND):
Rsc = R2 + R3||R4
And finally equivalent resistance is equal:
Req = Rop*Rsc = (R2 + R3)* (R2 + (R3 R4)/(R3 + R4))
But I don't know why.
And I'm not sure if this is correct.

 

Well OK I solve the gain of this circuit with "classic" opamp method.
And my previous post is completely wrong.

 

Hello again ... so you couldnt find the equivalent resisatnce ?!

 

Well yes I know the equivalent resistance.
If I look to my book to the chapter about two-port network theory I see this equation:
Req = R2+R4 + (R2*R4)/R3

PS.
Look here
http://wapedia.mobi/en/Two-port_network#6http://en.wikipedia.org/wiki/Two-port_network#ABCD-parameters
B = V2/I1 for V1=0 is equal Req
And know I suspect why. In op amp V1 = 0V but I1 >0A because I1 = I2 and V2 = Vout

 

Hello ... This is my first post and i hope from the members here to help me ...

In the circuit above I want to calculate the gain of the amplifier ... there is two ways to do it ... one is the regular and second it to calculate the equivalent resistance for R2, R3, R4 ... Can you help me in getting the equivalent resistance?

Thanks in advance

Note that R2, R3 and R4 are in the form of a T attenuator, or T-pad:

http://en.wikipedia.org/wiki/T-pad

The T-pad has two series branches (R2 and R4) and one shunt branch (R3).

You could convert it to a PI-pad:

http://en.wikipedia.org/wiki/PI-pad

The PI-pad has two shunt branches and one series branch. The PI-pad shunt branches do nothing because the one connected to the output is just another load on the output and contributes nothing to the feedback. The shunt branch connected to the - input does nothing because that node is a virtual ground. This leaves the series branch as the only contributer to the feedback, so this is probably what your problem wants you to calculate, calling it "equivalent resistance".

You can convert the T-pad to a PI-pad using the Y-Δ transformation:

http://en.wikipedia.org/wiki/Wye-delta

Knowing ahead of time that the two shunt branches of the PI-pad do nothing in this circuit, you need not even bother calculating them. Just calculate the branch that will be the series branch of the PI-pad; that's your Req.

 

Thanks alot loverly members ..
Is it possible The Electrician to show it more how do the shunt resistance have nothing to do ?
Can you prove it mathamatically if possible ...

Thanks in advance you really helped me

 

Re-draw the circuit with a PI-pad arrangement of the three resistors, R2, R3 and R4.

Analyze the circuit by any standard method, and show that the shunt branches are not present in the expression for the overall voltage gain.

Can you do this?

 

R a = R 2 + R 4 + ( R2 * R4 / R 3 )

do you mean that i do KVL in the below draw in the big loop and i ignore R b and R c ?

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R a = R 2 + R 4 + ( R2 * R4 / R 3 )

do you mean that i do KVL in the below draw in the big loop and i ignore R b and R c ?

​

Don't just ignore Rb and Rc.

Solve the network by whatever method you wish, such as KVL, including Rb and Rc in the analysis, and derive an expression for the voltage gain of the circuit.

Rb and Rc should not appear in the final gain expression, which shows that the gain is independent of Rb and Rc; in other words, Rb and Rc have no effect on the gain. This assumes that the opamp open loop gain is infinite, of course.