# Voltage division question

#### Henry Jyrkinson

Joined Feb 17, 2015
2
Hi here is my problem

So I need to solve Vout.

#### shteii01

Joined Feb 19, 2010
4,644
Are R1 and R4 in parallel?

#### Henry Jyrkinson

Joined Feb 17, 2015
2
Yes they are.

#### MikeML

Joined Oct 2, 2009
5,444
Write a KCL equation for the current in/out of node(Vout).

#### crutschow

Joined Mar 14, 2008
30,798
You can also convert each parallel pair of resistors to the equivalent single resistance and solve the voltage from that.

#### WBahn

Joined Mar 31, 2012
27,400
There's only one pair of resistors in parallel.

#### crutschow

Joined Mar 14, 2008
30,798
There's only one pair of resistors in parallel.
The op stated that R1 and R4 are in parallel.

#### WBahn

Joined Mar 31, 2012
27,400
The op stated that R1 and R4 are in parallel.
Yes. R1 and R4 are in parallel. Those are the ONLY two that are in parallel.

R2 and R3 are NOT.

#### crutschow

Joined Mar 14, 2008
30,798
Yes. R1 and R4 are in parallel. Those are the ONLY two that are in parallel.

R2 and R3 are NOT.
You are correct of course. Silly me, as you might have guessed, I didn't closely look at what I thought were two ground symbols.

#### WBahn

Joined Mar 31, 2012
27,400
You are correct of course. Silly me, as you might have guessed, I didn't closely look at what I thought were two ground symbols.
We've all done it. And we will all do it again. And again.

#### Dodgydave

Joined Jun 22, 2012
10,502
Work out the parallel resistance, (20K) then remove the resistor to ground (R3),and work out the current across the 90V supply, then work out the voltdrop across R2, subtract the 30V and that should be it...

#### WBahn

Joined Mar 31, 2012
27,400
Work out the parallel resistance, (20K) then remove the resistor to ground (R3),and work out the current across the 90V supply, then work out the voltdrop across R2, subtract the 30V and that should be it...
On what basis are you removing R3?

#### JoeJester

Joined Apr 26, 2005
4,390
I'm sure glad Henry Jyrkinson will get a good grade after all the work he's done to solve this problem.

#### WBahn

Joined Mar 31, 2012
27,400
I'm sure glad Henry Jyrkinson will get a good grade after all the work he's done to solve this problem.
Well, I guess we can give credit where credit is due -- he DID come back and answer one of the clarification questions that was asked. That's better than most!

He's also had to deal with some false hints, which can be frustrating but also very educational.

Still, I'm with you -- need to see some effort from him if there is much point going any further.