Bordodynov
- Joined May 20, 2015
- 3,431
I am sorry.
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Hi Bordodynov,I am sorry.
Hi Bordodynov,
Hi Bordodynov,I am sorry.
The frequency depends on the value of the capacitor C1 and the resistor R4 (F~1/(C1*R4)). Also depends on the amplitude. More amplitude, more period (less frequency). The amplitude depends on the rating of the divider (R1 and R2) and the feedback resistor R3. For linearity, I used current generators. This current generator is built on mirrors BCV61C and BCV62C. The generators are switched on in turn, depending on the output voltage of the comparator. When using a simple resistor, pieces of exponents are obtained. With small signals it's not scary.Hi Bordodynov,
i have tried your circuit and it performs well.
But i don't know how to change your amplitude or frequency of your circuit. Could you tell me about it?
And what do the component "bcv61c" and "bcv62c" mean?
Thanks a lot!
Jackie
Hi Bordodynov,With a transmission factor of -1, you apply 3.5 volts to the input, and a 2.5-volt supply voltage. Either increase the supply voltage, or make a transmission factor of -0.5. Replace the comparator with an operational amplifier and there will be no ejection. The truth is that the frequency decreases, but the frequency can be corrected by a capacitor or a resistor. You also need to add an inverting amplifier.
Hi Alec_t,I'm thinking the ADC would probably benefit from seeing a source impedance ~10k or less, so my circuit above could be modified by making C1=91p, R3=10k, R4=10Ω.
Hi Bordodynov,Unfortunately, the digital Schmitt trigger has a hysteresis variation and temperature dependence. Individual adjustment of frequency and amplitude is required. The comparator produces a more stable frequency.

Yes, i have seen that. Your ratio is 0.5. But now the output is as you said = (IN +TRI)/2, not = IN+TRI. Then it can't achieve my goal.I demonstrated the operation of the circuit with a 4-volt input signal. The output was 2 volts. I thought so. The circuit can operate with a signal greater than the supply voltage if the transmission factor is less than unity. I have a transmission ratio of 0.5. The input signal should be less than 4.9 volts.
Hi Bordodynov,I do not understand why you are not satisfied with the half signal. But then use +/- 5 volts power, and that operational amplifier, which I recommended (it will work with a total power of 10 volts). Otherwise, you will not get it.