Hello,

I found this voltage shifter: http://www.ti.com/lit/ds/symlink/txb0108.pdf
In the beginning the datasheet gives the range for VccA: 1.2 V to 3.6 V
but further on in the datasheet the absolute maximum ratings are given and then they say: -0.5V to 4.6V

So is it a problem to use this voltage shifter for translate 1V to 5V and visa versa?

 

Absolute maximum ratings are simply magnitudes beyond which the part may be damaged. They are always greater in magnitude than the normal or recommended levels. There is no guarantee that the circuit will behave properly if operated outside the recommended range.

If VccA is 1.2 to 3.6 V the part will operate as expected, provided all other criteria a met (both Vcc levels appropriate to logic levels, VccA less than or equal to VccB, etc.). No damage will result if VccA is within the range of -0.5 to 4.6 V, but it may not operate correctly. If you take VccA more negative than -0.5 V or more positive than 4.6 V the part may be damaged.

 

Oke i am a bit confused at the moment.

So the problem is:
i have a sensor with 10 digital outputs(internal adc).
the sensor is working at 1V and the MCU at 5V.

I thought i use a voltage shifter inbetween to set the right voltage level on both sides.
But what happens when the output is low at the sensor side? Is the voltage level still 5V on the other side?
Because otherwise there is no difference between high and low output from the sensor

 

someone who can help me?

 

You need to look carefully at the data sheet. Note Figure 8. It will do what you require provided the drivers on both sides are push-pull. It cannot be used with "open drain" outputs because of the way it senses which direction the signal is going.

You should also go to the TI website main page for the part. There you will find links to six applications notes that relate to this part and others that are similar.

 

You need to look carefully at the data sheet. Note Figure 8. It will do what you require provided the drivers on both sides are push-pull. It cannot be used with "open drain" outputs because of the way it senses which direction the signal is going.

You should also go to the TI website main page for the part. There you will find links to six applications notes that relate to this part and others that are similar.

thanks, i found a manual on the main page and i understand the working now!
For someone in the future, here is a great explanetion of the working:
http://www.ti.com/lit/ml/scyb018h/scyb018h.pdf