Hello!
So i have two diodes together and volatage 1V, the upper diode should be open and fully conduct current, but the second diode (reverse-biased) acts like a resistor with very high resitance? There should be some current in circuit, but how to calculate it, is this current only the leaking current from the reverse biased diode? And if I would make the source voltage something like 0,2V then the upper diode would not be opened, because it takes ~0,7V to open a diode, so then there would be even less current in circuit?
napos
So i have two diodes together and volatage 1V, the upper diode should be open and fully conduct current, but the second diode (reverse-biased) acts like a resistor with very high resitance? There should be some current in circuit, but how to calculate it, is this current only the leaking current from the reverse biased diode? And if I would make the source voltage something like 0,2V then the upper diode would not be opened, because it takes ~0,7V to open a diode, so then there would be even less current in circuit?
napos