Hi.I have some questions regarding the relationship between Turn on time,Turn on delay time and Rise time of a MOSFET.
This is merely a theoretical question because Im writing a test in 2 days and I want to check out my understanding.
Suppose we have a resistor in series with the mosfet in series with a voltage source XV.

Assuming that the threshold voltage VGS = 0(idealy),if we applied a 5V signal to the gate of the mosfet the turn on delay time would be the time needed for VGS to become 5V.During this time the current IDS of the MOSFET starts increasing until we reach the value of the current IDS at VGS=5V(from datasheet curve).
Then it takes some time for the voltage VDS of the MOSFET to go from XV to 0 and that's the rise time.So the turn on time = turn on delay time + rise time right?
Also why is it called rise time since voltage VDS drops to 0 from XV?

 

There's a nice explanation with graphs on page 6 of this application note
https://toshiba.semicon-storage.com/info/application_note_en_20230209_AKX00063.pdf?did=13415
I think that "rise time" applies to the rise of the current.

 

There's a nice explanation with graphs on page 6 of this application note
https://toshiba.semicon-storage.com/info/application_note_en_20230209_AKX00063.pdf?did=13415
I think that "rise time" applies to the rise of the current.

Thanks a lot Ian that helped me a lot!