The circuit would be fed back with a PID controller that makes it seek its stabilization, do you think that it works?The calculation procedure is as before when you replace the feedback resistor of the 1st opamp with the capacitive impedance Zc=1/jwC.
However, under real conditions the circuit will not work because of resistive positive feedback. There will be no stable DC operating point and the circuit will go into saturation.
No, I don`t think so. A PID controller will influence the dynamic behaviour of a circuit but it cannot fix a dc operating point.The circuit would be fed back with a PID controller that makes it seek its stabilization, do you think that it works?
Before I asked how to convert my plant into a circuit, since I was going to test the PID controller in a physical circuit and they gave me that circuit that has an unstable pole, so how do you recommend I model my function which is 1/ s - 2 in a circuit functional?No, I don`t think so. A PID controller will influence the dynamic behaviour of a circuit but it cannot fix a dc operating point.
In any case - you must avoid DC feedback with two inversions within the loop.
As a working example: The classical state variable filter (universal filter) consists of an integrator stage plus an inverting amplifier (as in your case) plus an additional integrating stage within one loop.
A voltage-controlled voltage source whose output grows exponentially.Before I asked how to convert my plant into a circuit, since I was going to test the PID controller in a physical circuit and they gave me that circuit that has an unstable pole, so how do you recommend I model my function which is 1/ s - 2 in a circuit functional?
Could I make use of an exponential amplifier?A voltage-controlled voltage source whose output grows exponentially.
I don't know what that is.Could I make use of an exponential amplifier?
by Jake Hertz
by Duane Benson
by Jake Hertz