I got Vo/Vi= R/(R1+Ls+R)

Vi is on the left and Vo is on the right


My question is: At what frequency will the magnitude of H(jw) be maximum?
I know at low frequencies it will be maximum but is that what i put for my answer?

 

Your transfer function is correct.

At any frequency greater than ω=0, the output is less than that at ω=0. So ω=0 would my answer.

 

when finding corner(cut off) frequency do I take

R/(R1+R),, which is the max value of H(jw), divided by square root of 2 and set that all equal to the transfer function?

 

I would think the corner frequency is ω=(R+R1)/L rads/sec

 

now I have the same circuit but the is a capacitor instead of an inductor.

Vo/Vi=R/(R1+(1/jw)+R)

2.) What frequency will the magnitude of H(jw) be maximum?
As frequency goes to infinity?

3.) What is the maximum value of the magnitude H(jw)
R/(R1+R)?

 

now I have the same circuit but the is a capacitor instead of an inductor.

Vo/Vi=R/(R1+(1/jw)+R)

2.) What frequency will the magnitude of H(jw) be maximum?
As frequency goes to infinity?

3.) What is the maximum value of the magnitude H(jw)
R/(R1+R)?

\(Vo/Vi=\frac{R}{R1+\frac{1}{j\omega C}+R}\)

2. Yes
3. Yes