Time module Relay

KeithWalker

Joined Jul 10, 2017
3,603
The electronics will probably work with a 9V supply, but the relay will be a problem. Even if it activates at that voltage, there may not be sufficient pressure between the contacts to ensure reliable continuity.
 

Thread Starter

GiannisMandelos

Joined Jan 19, 2019
43
The electronics will probably work with a 9V supply, but the relay will be a problem. Even if it activates at that voltage, there may not be sufficient pressure between the contacts to ensure reliable continuity.
Ok, so as far as the electronics are considered, we are safe to power the module with a 9 volt battery. That's my main concern, only the electronics of the module. I have tested the relay down to 10 Volt and it has the pressure to ensure a relaible continuity. I just don't want to burn the module's electronics. So, apart from the relay, you beleive tha the rest of electronics are safe, is that right?
 

Thread Starter

GiannisMandelos

Joined Jan 19, 2019
43
Yes. The module uses a NE555 chip, no problem at 9 volts.
Hi again! I would like to ask something more. The fact that the 12Vdc relay works at 9.5 Vdc input, does it mean that it is overworking due to the lack of energy, and there is danger to get burnt? Thank you!!
 

sghioto

Joined Dec 31, 2017
8,633
Hi again! I would like to ask something more. The fact that the 12Vdc relay works at 9.5 Vdc input, does it mean that it is overworking due to the lack of energy, and there is danger to get burnt? Thank you!!
No, nothings going to get burned.
The fact that it works at 9.5 volts is because the relay specs indicate the pickup voltage is 9 volts.
Are you wanting to operate the module from a 9 volt battery?
 

Thread Starter

GiannisMandelos

Joined Jan 19, 2019
43
Yes, in fact I power the relay module through a mini dc-dc converter that gets powered from a 9 volt battery. However, I have to keep the dc-dc converter's output regulated at 9,5 Volts as it parallely powers another IC in my project's circuit that strictly needs 9.5Vdc at it's input. I hope you understand. I tried it and it works fine. Thank you for ypur help!
 
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