Yes, a battery has (gives) voltage, even when it is an open circuit.so I need to calculate this loop:
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But it is an open circuit, does the battery give voltage? does the 4\Omega resistor drop voltage?
This diagram has I2 as the current flowing downward in the 2 Ω resistor. But in your original diagram I2 was defined as the current flowing to the right through the adjacent 4 Ω resistor (the one to the left). You need to be consistent in your use of variables.so I need to calculate this loop:
But it is an open circuit, does the battery give voltage? does the 4\Omega resistor drop voltage?
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