Hello, I have an rf signal that needs to be channelled to out1 or out2.
I have -12V and gnd power rails.
From the data sheet I need V1 and V2 be the inverse for the switching to work properly.
I want to use a push button to switch between the two states of the switch.
how can I implemdent in analog way such a method that push button would switch V1 from 0 to -5 and V2 from -5 to 0?

https://cdn.macom.com/datasheets/MASW-008322.pdf
https://catalog.quanticxmw.com/item/x-mwblocks/switches/xm-a351-0604d

 

What's an 'analog' way?

If you mean with discrete transistors rather than logic gates, then yes it is possible, needs 6 transistors, a few diodes, and about 15 or so passive parts...

Of course, you could use a -5v regulator (7905) a couple of capacitors and a push-on, push-off SPDT switch...

 

Hello Irving , what spdt switch you recommend to switch as does U1?

Thanks.

 

If it has to be a push button, use it to clock a flip-flop (e.g. D-FF). Power the FF from 0V (VCC) and -5V (GND). Debouncing the push button will be required. The usual RC-filter and Schmitt Trigger inverting gate would do.

 

Hi Yef, any latching ie push-on/push-off push button should do, either PCB or their panel mounted equivalent. Below are a few PCB examples from the RS Catalog...

@0ri0n 's point, regarding switch bounce is an interesting one, however since we are switching the supply over any bounce on contact closure would have minimal effect. You could put a 1 - 10uF capacitor across those 1k resistors to absorb any bounce.