I think I may be over-analyzing this question...
Determine the source and destination Ethernet MAC addresses from the following Ethernet frame header HEX dump....
00 13 49 63 5c 68 c0 cb 38 87 8a a7 08 00
according to this site
http://www.erg.abdn.ac.uk/~gorry/eg3561/lan-pages/mac.html
the destination is the first group of 6 bytes and the source is the second group of 6 bytes. Is it really that easy?
Source = c0:cb:38:87:8a:a7
Destination = 00:13:49:63:5c:68
Determine the source and destination Ethernet MAC addresses from the following Ethernet frame header HEX dump....
00 13 49 63 5c 68 c0 cb 38 87 8a a7 08 00
according to this site
http://www.erg.abdn.ac.uk/~gorry/eg3561/lan-pages/mac.html
the destination is the first group of 6 bytes and the source is the second group of 6 bytes. Is it really that easy?
Source = c0:cb:38:87:8a:a7
Destination = 00:13:49:63:5c:68