Input signal is sine wave - so, over time that signal changes amplitude - i just want DC voltage that follows that changes as I said some kind of DC follower.Still NOT clear. Is the input signal
a sine wave
a square wave
a triangle wave
a sawtooth wave
or some other wave shape?
It sounds like you want a DC output voltage that is proportional to the peak-to-peak amplitude of the input waveform. Is this correct?
ak
Please draw the incoming waveform (label 0V and peak) and outgoing waveform at 0V, 5mV and 30mVInput signal is sine wave - so, over time that signal changes amplitude - i just want DC voltage that follows that changes as I said some kind of DC follower.
The reason for high impendance : I dont want to sink input signal, it is like digital voltmeter ...after that I am going to "transfer" that DC voltage using 4-20mA using AD694 but that has been already solved, the problem is just that input circuit that has to be precise (as we can to make it precisely)
He said that when the input is 0V to +30mV peak-to-peak then the output must be amplified to 0V to +5V peak-to-peak.Is the output to be linear or in decibels?
I was just wondering if he wanted the output on a logarithmic scale, so 5V out = 30mV in, 4V out = 3mV in, 3V out = 300uV in.He said that when the input is 0V to +30mV peak-to-peak then the output must be amplified to 0V to +5V peak-to-peak.
Decibels are important since the max flat frequency response of an opamp is shown in its datasheet on a frequency/gain graph.
by Jake Hertz
by Jake Hertz
by Aaron Carman
by Jake Hertz