Hello,

Looking for some help with the following problem:

A single phase bridge rectifier output voltage is |118*1.414*sin(120*pi*t). Find the RMS value, period, and the DC component of this voltage.

I have the RMS (118 V) and period (1/60 seconds). I'm struggling with the DC component. Any ideas?

Thanks

 

Do you mean its input is 118*1.414*sin(120*pi*t)?

 

Hello,

Take a look at this PDF.
http://technology.niagarac.on.ca/courses/etec1120/Files/Unit12.pdf

Greetings,
Bertus

 

Nope. The problem reads output voltage...

 

The output of a rectifier is not a sinewave but anyway. The DC voltage of a full wave rectifier equals:

Vdc=2*Vm/pi

where Vm is the peak output voltage

 

Mik3 Thanks. I know that's why I'm confused.

Bertus, thank you for the link. Very helpful.

 

There's a modulus bar at the beginning of the expression, but not at the end. I think it should be:

| 118*1.414*sin(120*pi*t) |

Then the question makes sense, and the output is indeed as expressed.

 

There's a modulus bar at the beginning of the expression, but not at the end. I think it should be:

| 118*1.414*sin(120*pi*t) |

Then the question makes sense, and the output is indeed as expressed.

In this way yes, it is correct.

 

The output of a rectifier is not a sinewave but anyway. The DC voltage of a full wave rectifier equals:

Vdc=2*Vm/pi

where Vm is the peak output voltage

Hi..I am new and found this really great forum. Thanks

I need help on my church guitar amp on the power transfomer. Here is the line :

Main AC input 220AC -->power transformer --> single phase rectifier-->output 22Vdc.

The problem is I dont know what is the power transformer's step down voltage? Why it does not say any info on the transformer plus its already been thrown away. I have attached the schematic of the amp.

Many thanks.
Jimmi