sine wave shaper

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lalalu

Joined Aug 16, 2009
3
Hello all

I am having trouble understanding a waveform shaping circuit that I found on the internet.

My task is to generate a sine wave (adjustable low frequency range). My plan is to use a vco to generate triangular wave and then change it into a sine wave. I was thinking of using the breakpoint method, and then I found this circuit.

So my question is what is the purpose of the opamp at the end? To smoothen the peak? or is this just aa normal feedback circuit. I also didnt get how the diodes work here, is this just a clipper circuit? I simulated the circuit in spice and found out that the circuit works just fine with only 2 diodes and 1 resistor (+side). Weird


Anyway I would appreciate it if someone could explain to me how the circuit work, or at least just the name of the circuit. Searching sine wave shaper blindly these past few days didnt yield much result. Thank you
 

jlcstrat

Joined Jun 19, 2009
58
It would appear the opamp is just used to amplify the signal...The diodes clip the signal to give it more of a sinusoidal shape...I'm only a student myself, but that would be my best guess
 

Audioguru

Joined Dec 20, 2007
11,248
A ICL8038 and an XR2206 function generator IC uses multiple breakpoints with diodes to convert a triangle wave into a sine-wave with horrible distortion.

The circuit that has only three breakpoints is much worse.
 

Audioguru

Joined Dec 20, 2007
11,248
You don't need an HP distortion analyser when the distortion is as high as the sine-wave made with a few breakpoints. You can hear the buzzing distortion.
 

Audioguru

Joined Dec 20, 2007
11,248
A Cmos digital inverter that is self-biased can be used to smooth a triangle-wave into a pretty good looking sine-wave but its even harmonics are not as low as they should be.
The inverter "compresses" the peaks of the triangle-wave.
 

danny2

Joined Oct 28, 2009
29
how to generate the 50Hz frequency of this sine waveform?

i had connect triangular waveform circuit to your circuit,i get the frequency of the 100Hz at the output of U3 in the schematic.

i have done the calculation for the triangular generator.the formular is F=R1/4(C1)(R9)(R3).the value for R1=100k,C1=0.1u,R9=417k,R3=12k,the frequency obtain is 50Hz,but then when i simulate this circuit,i get the sinewave of 100Hz,doen't it suppose to follow the triangular frequency?I need help on this.
 

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