Can anyone solve this problem to find the current in the circuit please? I need it badly.
No, I just don't need the 'answer', I need a sollution step by step. I tried to solve this in many ways, but it always ends with a quardatic equation whitch is 15i^2-23i+16=0. I am pissed off & I posted it here.So do you just want someone to solve it and give you the answer?
Can anyone solve this problem to find the current in the circuit please? I need it badly.
Can anyone solve this problem to find the current in the circuit please? I need it badly.
What's wrong with getting a quadratic equation?No, I just don't need the 'answer', I need a sollution step by step. I tried to solve this in many ways, but it always ends with a quardatic equation whitch is 15i^2-23i+16=0. I am pissed off & I posted it here.
Yes and no. The given information is sufficient, it's just that no solution exists for those particular values. The most total power than can be delivered to the set of parallel resistors is a tad under 90 W.That problem is not solvable with the information given.
The answer will come with complex form. Please just confirm me my steps are right, or wrong.What's wrong with getting a quadratic equation?
That's not the problem. If the powers given had each been, say, 1/2 of what they presently are, the solution would be easy to find.So if a Resistance value and a Power value given in series with a input voltage, it is not possible to find the circuit current?
Even if we ignore units, that last line is not consistent with the line above it.The answer will come with complex form. Please just confirm me my steps are right, or wrong.
Oh yeah...you're right. It is a doozy of a problem though!Yes and no. The given information is sufficient, it's just that no solution exists for those particular values. The most total power than can be delivered to the set of parallel resistors is a tad under 90 W.
Oh, and thank you for showing your work. Now it is obvious that you are NOT just looking for someone to do your work for you and that you HAVE actually put in some quality effort. We are now in a much better place to help you make sense of the problem and why no solution exists, as stated.The answer will come with complex form. Please just confirm me my steps are right, or wrong.
Depending on how you approach it, it can be either a brain twister or it can be easy. I started down the brain twist path initially, but backed off and came at it another way. I should have looked at the maximum power transfer possible at that point, but didn't until after my second way, which involves solving a quadratic that can be trivially written down by inspection, yielded no real solutions and I wanted to understand why not. The TS took a slightly different route than I did, but still used an approach that is very commendable.Oh yeah...you're right. It is a doozy of a problem though!
You can always add a negative resistance.Depending on how you approach it, it can be either a brain twister or it can be easy. I started down the brain twist path initially, but backed off and came at it another way. I should have looked at the maximum power transfer possible at that point, but didn't until after my second way, which involves solving a quadratic that can be trivially written down by inspection, yielded no real solutions and I wanted to understand why not. The TS took a slightly different route than I did, but still used an approach that is very commendable.
Works for me! Does Radio Shack still carry them thar negisters?You can always add a negative resistance.
Track the units is the right way to write down an equation? This is new to me & it is not generally practiced here. By the way thanks for your effort to this problemEven if we ignore units, that last line is not consistent with the line above it.
You need to properly track your units through your work. Your last line should be
(15 Ω)·I² - (23 V)·I + (16 W) = 0
If we divide by sides by 1 Ω, we have
(15)·I² - (23 A)·I + (16 A²) = 0
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by Luke James
by Gary Elinoff