Thevenin's Method can be applied to the resistive divider R2(leftmost) and R1 to get the Vth and Rth.Could you possibly tell me if you could also solve this circuit by finding the Thevenin Equivalent of the linear half of the circuit, and then use KVL to find Id? This is how I was attempting to solve it, and how I think I've seen similar problems solved. But I get a different answer. I want to know if this method is not applicable, or if I'm making an error along the way some where.
I did notice and wonder about that. :/It should "trouble" you that (in the absence of any controlled sources) you get a Thevenin voltage greater than the original source voltage.
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by Jake Hertz
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by Jake Hertz