Would anybody be so kind as to help a dummy out? I tried to read http://forum.allaboutcircuits.com/threads/project-auxilliary-gas-gauge-for-a-motorcycle.29644/ but it was over my head. My fuel sending unit outputs 0-700 ohms. My gas gauge reads 33-240. Is there any simple way a lamen can understand to make them match up? Please be detailed if you could...thank you.

 

Can you give a better explanation for the gauge reading 33-240? Does that mean a series resistance of 33 ohms for Empty and series resistance of 240 ohms for full reading? At what voltage?

 

There are just 2 wires, no supplied voltage for sender but gauge runs on 10-16 volts. 0-700 700 empty on sender, 33-240 240 empty on gauge

 

I'm more confused than before. Your guage reads 33 - 240...what? Please provides all the details. Most of us won't guess and won't hang around for the details to drip out.

 

A traditional fuel gauge sender is a simple variable resistor. It's a fine wire wound around a support, with a spring-held wiper that moves with the float. Depending where the wiper touches the wire windings, indicating the float position, a varied resistance is seen at the output.

I have no idea what you are talking about with your gauge.

 

How many terminals on the gauge? Two or Three?

If two, is is wired like this?



Be advised that it is really hard to make this work. You really need to get a sender matched to the gauge...

 

If the guage is looking for 33 - 240 ohms and say, 14V, or eqivalently 424 - 58mA, I suppose you could use a voltage/current converter calibrated to those current outputs.

PS: The thread in the link uses a voltage scaler, so I'mclearly out of my league here.