Please, please, please, please help me. help me


Questions:

Three impedance are connected in series across a supply of V=100 V, 1.0 kHz supply:

# 125 Micro Henry inductor that a 0.4 ohm resistance. (Note: V1= Voltage across inductor)
# 20 Ohm Resistor, (Note V2= voltage across resistor)
# 120 pF capacitor in parallel with a 150 ohm resistor, (V3= voltage across these two components.)

a. Sketch the circuit diagram

b. Calculate the magnitude of the voltage V1 across the first impedance

c. Calculate the magnitude of the voltage V3 across the third impedance

 

Please don't hijack someone else's thread. Not only is it rude, it causes nothing but chaos and confusion.

Start a thread of your own, state your problem, and then show YOUR attempt to solve YOUR homework problem so that we have a starting point for discussion.

 

Hello,

You just hyjacked an existing thread:
http://forum.allaboutcircuits.com/threads/rlc-in-parallel-resonance-and-multisim.104649/

Now you have a thread of your own.

Bertus

 

# 125 Micro Henry inductor that a 0.4 ohm resistance.

Makes no sense.

 

Makes no sense.

Hi,

It appears that the inductor has a series resistance of it's own, the ESR. This it typical.

 

Please, please, please, please help me. help me


Questions:

Three impedance are connected in series across a supply of V=100 V, 1.0 kHz supply:

# 125 Micro Henry inductor that a 0.4 ohm resistance. (Note: V1= Voltage across inductor)
# 20 Ohm Resistor, (Note V2= voltage across resistor)
# 120 pF capacitor in parallel with a 150 ohm resistor, (V3= voltage across these two components.)

a. Sketch the circuit diagram

b. Calculate the magnitude of the voltage V1 across the first impedance

c. Calculate the magnitude of the voltage V3 across the third impedance

Hi,

Do you know how to calculate complex impedances and use them in an analysis?

 

Hi,

It appears that the inductor has a series resistance of it's own, the ESR. This it typical.

So the total impedance of the inductor is: jwL+ESR? j(1 kHz)(125 uH)+0.4 Ohm?

 

The dc resistance of the coil wire is 0.4 ohms in this example. It is typically represented by adding a resistor to the circuit, unless of course, you can just add that parameter to your simulation software. Adding the resistor would demonstrate clarity in your thinking.

 

So the total impedance of the inductor is: jwL+ESR? j(1 kHz)(125 uH)+0.4 Ohm?

Hi,

Yes. You can actually think of this in at least two ways:
1. The inductor has a series resistor of Rs so the impedance is j*w*L+Rs (Rs is the ESR as you noted)
2. If there is an already present resistor in series with the inductor then just add it to that resistance. So if the resistor was 100 ohms just add 0.4 to that and get 100.4 ohms. This is only valid if the resistor is in series with the inductor and there is nothing else connected to that lead of the inductor.
.
Inductors always have at least some series resistance so we end up doing this for almost every inductor. This is more important in power circuits because it affects efficiency and even whether or not the circuit works as all sometimes. Some boost circuits wont work at all if the series resistance of the inductor is above a certain value because the inductor can never absorb enough energy from the power supply to allow the output to be boosted to a higher level with the required current demand.

 

Hi,

Yes. You can actually think of this in at least two ways:
1. The inductor has a series resistor of Rs so the impedance is j*w*L+Rs (Rs is the ESR as you noted)
2. If there is an already present resistor in series with the inductor then just add it to that resistance. So if the resistor was 100 ohms just add 0.4 to that and get 100.4 ohms. This is only valid if the resistor is in series with the inductor and there is nothing else connected to that lead of the inductor.
.
Inductors always have at least some series resistance so we end up doing this for almost every inductor. This is more important in power circuits because it affects efficiency and even whether or not the circuit works as all sometimes. Some boost circuits wont work at all if the series resistance of the inductor is above a certain value because the inductor can never absorb enough energy from the power supply to allow the output to be boosted to a higher level with the required current demand.

Thank you. I don't think I ever had this in my circuits class.

 

So the total impedance of the inductor is: jwL+ESR? j(1 kHz)(125 uH)+0.4 Ohm?

Yes, this is correct because you properly used units. The unit Hz·H IS a unit of resistance, but just not ohms. There are 6.28Ω per hertz-henry.