Thankshi,
Look at this, 3.6kHz tone while the switch is closed.
Simplified version of your circuit.
E
Update MOSFET .
Try a FDS4072N3
Ok thank you, I understand now. I thought you proposed those values for that reasonhi G,
I am not proposing a low value resistor, it is a simple simulation of a MOSFET switch.
When using a voltage regulator you must use decoupling capacitors.
Your circuit has no values for the components or the value of Vcc
The simulated circuit will not give you a 1sec On/Off of a 3kHz signal.
Are you asking for a design of fully working circuit.??
If so please specify which type of MOSFET you have available and the 9V reg type, value of Vcc etc...
E
It would help *greatly* if you posted the schematic in your head; without it, this is a guess. You can do this with the NO switch and one resistor.I want to use a NO switch, so using a NC switch is not an option.
Unit price for the N MOSFET is 32cents. There are other SOT23 with smaller package that can drain around 0,5Ahi G,
The DMN3018SSS N MOSFET looks suitable, bit over rated in Drain current, what price are you paying.?
Do you still want a 1Sec On/Off rate of a 3.5kHz square wave drive for the piezo.?
Have you considered a 9v audio beeper instead of the piezo, it would cut the need of a second 555.
E
hi G.I think that achieving a 50% duty cicle would produce sound intermittently and without the need of an extra 555; even if the intervals are shorter than 1sec
Ok, it can take the 9Vhi G,
The piezo you posted requires a 4kHz square wave drive, of course you can set the 555 to give a 50:50 drive, but it will sound continuously while the 9V is applied.
ie: while the switch is Closed.
Is that OK.?
Look at the Vppk to Drive.!
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View attachment 217223
How would you do that? I truly dont know. I really thought that the easiest way to drive the buzzer was using the 555 as oscillatorYou can also use a CMOS inverter as an oscillator and then the other gates as an amplifier to drive the piezo device and have less standby current, and only need one capacitor. and then the switch can just stop the oscillation and so the total current draw will be very small. This idea just hit me while eating breakfast.
That will give 50:50 with an idealized 555 (or a CMOS 555) with output equal to the supply.hi G,
Look at this option for 50:50.
E
Ok, it can take the 9V
It is a bit more disturbing to have the whole time the sound but I think it would be smaller the circuit just using one 555
One CMOD inverter as a
How would you do that? I truly dont know. I really thought that the easiest way to drive the buzzer was using the 555 as oscillator an oscillator, with a capacitor to common and a resisttor for feedback, followed by another inverter driving two in parallel, while the oscillator output direct drives the other two inverters for the opposite phase. The piezo element connects betrween the outputs of the two sets of two inverters. The closed switch keeps the input ogf that oscillator held low, and none of the gates are outputting any current until oscillation starts. One resistor, one capacitor, and one 4049 hex inverter IC. That is about as simple as I can make it. And the piezo will be rather lioud with 2x Vcc as rge drive voltage;
Did you consider MrBill2 suggestion in post #59?Hello everyone,
I have a circuit regulated with a LDO 9VDC that uses a 555 timer and I want it to work when I activate the circuit with a magnet. Willing to do that I chose a reed switch and as I could read, most reed switches have a NO contact.
That said, the normal application would make the 555 work when you approach a magnet to the switch and the contact is closed; but I want to reverse it, I want to make the 555 timer work when the magnet is far from the swtich and stop working when the magnet gets close and the switch closes.
What do you think is the most efficient way to do this? I want to use a NO switch, so using a NC switch is not an option.