Resonant Frequency

Thread Starter

HARRYthefrog

Joined Apr 7, 2021
5
I need to find the resonant frequency of a RLC circuit but not sure if i have done it right or not :
so i did

Spec:
50mH
0.01uF
120R
1V dc

1/2pi sqrt 50mH*10^-3*0.01uF*10^-6=7118 Hz (is this right ) ?
 

LvW

Joined Jun 13, 2013
1,299
I need to find the resonant frequency of a RLC circuit but not sure if i have done it right or not :
so i did

Spec:
50mH
0.01uF
120R
1V dc

1/2pi sqrt 50mH*10^-3*0.01uF*10^-6=7118 Hz (is this right ) ?
How do you define "resonance"?
The result depends on the position of the resistor - in series to L or in parallel to L||C ?
 

Thread Starter

HARRYthefrog

Joined Apr 7, 2021
5
How do you define "resonance"?
The result depends on the position of the resistor - in series to L or in parallel to L||C ?
i did it by putting everything in series ,the questions that i was given just said RLC so i just put it in series .
 

Ian0

Joined Aug 7, 2020
3,186
Does it make any difference? Isn't the resonant frequency the same regardless of the position of R and whether it is series or parallel resonance. It's the Q that changes.
 

LvW

Joined Jun 13, 2013
1,299
Does it make any difference? Isn't the resonant frequency the same regardless of the position of R and whether it is series or parallel resonance. It's the Q that changes.
Yes - it makes a difference. When R is in series to L only (and not to the parallel combination L||C) the resonant point is not simply SQRT(1/LC). The dame applies when L in series to C with R||C.
Try to find the difference while simply applying the definition for resonance.
 

Ian0

Joined Aug 7, 2020
3,186
Yes - it makes a difference. When R is in series to L only (and not to the parallel combination L||C) the resonant point is not simply SQRT(1/LC). The same applies when L in series to C with R||C.
Try to find the difference while simply applying the definition for resonance.
You're correct - I wasn't thinking of resonant circuits quite that advanced!
 
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