Hi,

I have a receiver with an impedance of 50Ohms. I have calculated the minimum receiver sensitivity to be -10dB.

Is there a way I can express the sensitivity in Volts? Can I convert the dB to power then calculate V = P/(R^2)

Thanks

 

Hello,

It can not be -10dB.
It is likely -10dBμV.
So the level is 10 dB lower than 1 μV.
The sensitivity will be about 0.3 μV.

Read the attached PDF for more info.

Bertus

 

Hi,

Please help me understand. I have a transmitter of 10watts (40dB) and I need to know what the minimum sensitivity of my receiver needs to be if I have losses of 20dB and need to allow for an additional margin of 30dB. Which is why I got -10dB.

So was trying to convert the sensitivity to a voltage value.

But I still need to get my head round a few things clearly.

 

Hello,

Decibels are a ratio between powers or voltages.
There must be a reference to calculate the power or voltage.
Read the PDF I gave you.

The power of your transmitter is quite high with the mentioned 10 Watts.
It is quite normal for a communication receiver to have a sensitivity of the 0.3 μV, I mentioned.

Bertus

 

Hi,

Please help me understand. I have a transmitter of 10watts (40dB) and I need to know what the minimum sensitivity of my receiver needs to be if I have losses of 20dB and need to allow for an additional margin of 30dB. Which is why I got -10dB.

So was trying to convert the sensitivity to a voltage value.

But I still need to get my head round a few things clearly.

10W are not 40dB, but 40dBmW often the W of dBmW is omitted when for instance working with microwave circuits if all values are small.
Not to be confused with dBmV

John BG

 

it would greatly assist the readers of your question to have the question supported with more details like:

1.- transmitter specs: model, circuit, block diagram, a photo
2.- same for the receiver: