Hi All,
I have a question regarding a proportional valve that I just bought from Clippard.
It's the EVP series with the following coil information (http://www.clippard.com/cms/wiki/evp-selection-tips):-
Voltage range: 0 to 20 V
Nominal voltage: 20 V
Coil resistance: 218 Ohm (measured 211 Ohm)
Max.current: 93 mA (probably a bit higher as the measured resistance is slightly different)
I'm planning to drive this with PWM from an Arduino board whose PWM output is from 0 to 5 volts. I'll be amplifying this with a BJT in common emitter mode. Since the gain is basically Rc/Re in emitter degeneration mode, I know I can set the gain to 4 so that the 0 to 5 V of the Arduino goes to 0 to 20 V at the collector output.
However, I'm thinking that if I use the 5 V DC from the Arduino itself, the gain will be clipped at 5 V (basically, I'm just trying to use minimum number of power supplies unless absolutely essential) in which case, I do not need the BJT at all. So the question here is: will the valve close and open completely if I use 0 to 5 V instead of 0 to 20 V? The link above says the valve only cares about the current which corresponds to the amount of travel. So can I assume that the 93 mA (which comes from dividing the nominal voltage by the coil resistance) is the current at which the valve opens fully or is it the current beyond which the coil burns up?
Also, I guess adding the valve in series with the Rc should be enough to limit the current to less than or equal to 93 mA?
I would appreciate your inputs on this before I start testing the actual circuit.
Thank you!
I have a question regarding a proportional valve that I just bought from Clippard.
It's the EVP series with the following coil information (http://www.clippard.com/cms/wiki/evp-selection-tips):-
Voltage range: 0 to 20 V
Nominal voltage: 20 V
Coil resistance: 218 Ohm (measured 211 Ohm)
Max.current: 93 mA (probably a bit higher as the measured resistance is slightly different)
I'm planning to drive this with PWM from an Arduino board whose PWM output is from 0 to 5 volts. I'll be amplifying this with a BJT in common emitter mode. Since the gain is basically Rc/Re in emitter degeneration mode, I know I can set the gain to 4 so that the 0 to 5 V of the Arduino goes to 0 to 20 V at the collector output.
However, I'm thinking that if I use the 5 V DC from the Arduino itself, the gain will be clipped at 5 V (basically, I'm just trying to use minimum number of power supplies unless absolutely essential) in which case, I do not need the BJT at all. So the question here is: will the valve close and open completely if I use 0 to 5 V instead of 0 to 20 V? The link above says the valve only cares about the current which corresponds to the amount of travel. So can I assume that the 93 mA (which comes from dividing the nominal voltage by the coil resistance) is the current at which the valve opens fully or is it the current beyond which the coil burns up?
Also, I guess adding the valve in series with the Rc should be enough to limit the current to less than or equal to 93 mA?
I would appreciate your inputs on this before I start testing the actual circuit.
Thank you!