PNP state not acting according to wikipedia

Thread Starter

yef smith

Joined Aug 2, 2020
1,476
Hello, I understood that I need to learn how to charecterise properly the PNP in my circuit.
I saw a circuit in a manual shown below.
I want to change this circuit in two ways:

1. to control the PNP with voltage source and resistors.
2.to determine current direction using voltage sorce and resistors
3.emitter needs to be connected to the higher potential

What circuit configuration can recreat the plot shown below?
Ltspice file is attached.
Thanks.

1742847396212.png
 

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WBahn

Joined Mar 31, 2012
33,051
Hello,I want to create the same plot purely with resistor and voltage source ,whar configuration you reccomend?
Thanks.
Do those plots look linear to you?

As in, for each simulation, the plot is a single straight line that goes through the origin?

If not, then what makes you think that you can use a (constant) voltage source and a resistor and create a circuit that has a transition from one straight line behavior to another?
 

Thread Starter

yef smith

Joined Aug 2, 2020
1,476
Hello,As you can see below I have a current plot which is created by the sweeping.
I have tried to create the same kind of plot in the configuration shown in the photo at the end .
However I get a tottaly different plot.
Where did i go wrong?
Thanks.

1743336874501.png

1743338697572.png
 

Thread Starter

yef smith

Joined Aug 2, 2020
1,476
Hello, In PNP current flows out of the base port and Ve-Vb>0.7 for conduction.
given the table below my PNP is in saturation state.
I need to increase the current in the following configuration.
from mathematical point of view as shown in the mathematical expression I developed below .
so by this math If i reduce the R3 it will not play much role in Ib ,but if R1 in the denominator is being multiplied by beta.
Two questions:
1. R3 is not only current limiting , R1 can control Ib much stronger ,correct?
2.given the configuration below hown Can i create such plot?
Thanks.

V2-Ib*R3+Vbe+R1*beta*Ib=15
Ib(R1*beta-R3)=15-Vbe-V2
Ib=(15-Vbe-V2)/(R1*beta-R3)
1743412953639.png1743412783099.png
1743410687289.png

1743411960731.png

1743417099683.png
 

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