Why the peak inverse value of a full wave rectifier is 2vm.....As i know peak inverse value is the maximum voltage that a diode can resist in reverse bias
yes i am reffering to tapped secondary arrangement.Under reverse bias, a rectifier diode must withstand the absolute value of the peak (inverse) supply EMF plus, the charge on the filter (hence 2*supply peak) --- That said I'm not certain I understand your question inasmuch as these considerations are not typically applicable to bridge rectifiers...
Are you referring to a taped secondary arrangement? (in which case, for reasons similar to those discussed above, the rectifiers must withstand twice the output EMF)
Best regards
HP
A taped secondary scheme may be viewed as a pair of 'tandem' half-wave rectifiers (each side of the tap) -- bearing that in mind please refer to the opening paragraph of my initial post on this thread...yes i am reffering to tapped secondary arrangement.
With no load; the reservoir capacitor will charge to the AC peak value, so the rectifier must withstand that plus the AC peak value when it swings the other way.Why the peak inverse value of a full wave rectifier is 2vm.....As i know peak inverse value is the maximum voltage that a diode can resist in reverse bias
PC monitors supplied for the UK system usuall came with at least 600V PIV bridge rectifiers, many had 800V types. Of course a bridge rectifier has 2 diodes in series at any one time - so the actual withstand was 1200 to 1600V.Piv on diodes is twice the maximum AC voltage,so if your rectifying say 230V, you need a piv of 500v to be safe.
Ahh... 2 x Vmax.Why the peak inverse value of a full wave rectifier is 2vm.....As i know peak inverse value is the maximum voltage that a diode can resist in reverse bias
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