How to build a circuit that will turn a light off when it gets dark.
I thought that usually you want to do the opposite: turn a light ON when it gets dark.How to build a circuit that will turn a light off when it gets dark.
Most light sensitive circuits consist of a light dependent resistor (LDR) and a bias or load resistor.I have found circuits that create a night light where a light turns on when it gets dark. I need the opposite.
I need a circuit that will allow a light to run continuously on 9 volts until it gets dark. Then I would like it to turn the light off.
Can anyone help?
What circuit?Thank you for the help. I was able to build the circuit and it works as described. The light turns off when it gets dark.
Next question I have is that the light is very dim. I assume the resistors are reducing the current flow? Is there a way for me to have full current running to the light?
I did change the transistor BC547 for a 2N3904 would that make a difference?
If you mean the voltage across the LED, that's to be expected. What is the maximum current rating/specification of your LED?the output voltage to my light is less than 3 volts
It depends on the LDR chosen. Try replacing R2 with a higher value resistor such as 10kΩ or replace it with a 10k-100kΩ variable resistor to allow you to adjust the switching threshold.This is the circuit I built. My battery is a 9 volt....but the output voltage to my light is less than 3 volts. As I mentioned I substituted a 2N3904 Transistor for the BC547 recommended in the schematic.