Re post #159 your diagram is correct. (If you reverse the polarity it will behave like a forward biased normal diode so it would have about 0.7 volts across the junction.) You just use ohms law to work out the resistor value. As it is a 9.1 volt zener you must more than 9.1 volts available. So your 12 volt power supply is your only option. So you will have 2.9 volts across the resistor. (We will call it 3 volts to make it easier to the calculations in our heads.) From the data sheet the voltage rating is given with a current of 5 mA. So R = 3/0.005 ohms = 600 ohms. As you have such a limited stock of resistors you can use three 200 ohm resistors in series. I don't know what you mean by "the common lead" in your last sentence.
Re post #160 I think that that gives a reasonable description of you problem. They will probable ask you questions and ask you to do various things to try to isolate the problem.
Les.
Re post #160 I think that that gives a reasonable description of you problem. They will probable ask you questions and ask you to do various things to try to isolate the problem.
Les.