hello,
i already have multiple core branches running across the flat (12,24V), i wanted to get rid of the batteries powering philips hue motion sensor

1) already installed on 12V branch , 3.3V pololu brick.

2) the chatgpt advised that 3.3v it too much and it might be better to dump it to 2.7-2.8V
using the following components

Core

• U1: MCP1700-3002 (3.0 V LDO)
• C1 (input cap): 1 µF ceramic (X5R/X7R)
• C2 (output cap): 1 µF ceramic

Optional safety drop

• D1: Schottky diode (e.g. 1N5817, BAT54)

Is that a correct recommendation/ and should i proceed with that, could you advise?

Thank you!

 

I don’t know how much current it takes but a silicon diode would probably suffice to drop 3.3V to 2.7V.

 

@Jerry-Hat-Trick i think like 100-200mA

 

An IN4004 diode should work, it’ll handle up to 1A current

 

Since really FRESH small batteries may deliver 1.65 volts initially, that is the voltage that I will pick to use. So the output oftwo fresh batteries with no load would be 3.3 volts. Then the "Phillips Hue Motion sensor" includes U1: MCP1700-3002 (3.0 V LDO) which is a regulator, it appears. So a supply of 3.3 volts should work quite well. With the connected device including that 3.0 volts regulator, why drop the supply voltage below that??

 

If you are not certain, consider the LM2596 DC/DC converter module, inexpensive and widely available. Up to 35V input can be dropped to anywhere between 1.25V and 30V. In your case I’d use a 12V input and adjust the output to 2.75V

 

If the current draw is as low as 100mA, how long will the two AA batteries last?? So MY GUESS , based on the supply battery size, is that the current draw is less.